x^2-(1/2)x-1<0怎么解
来源:百度知道 编辑:UC知道 时间:2024/09/28 10:46:22
求 x^2-(1/2)x-1<0 中的X的值,最好写一下过程啦
解:
x^2-1/2*x-1<0
x^2-2*x*(1/4)+(1/4)^2-(1/4)^2-1<0
(x-1/4)^2-17/16<0
(x-1/4)^2-(1/4*根号17)^2<0
(x-1/4+1/4*根号17)(x-1/4-1/4*根号17)<0
1/4-1/4*根号17<x<1/4+1/4*根号17
x^2-1/2x+1/16-1/16=1,(x-1/4)^2=17/16,x=(1加减根17)/4
解:
x^2-1/2*x-1<0
x^2-2*x*(1/4)+(1/4)^2-(1/4)^2-1<0
(x-1/4)^2-17/16<0
(x-1/4)^2-(1/4*根号17)^2<0
(x-1/4+1/4*根号17)(x-1/4-1/4*根号17)<0
1/4-1/4*根号17<x<1/4+1/4*根号17 你可以自己解解看,主要自己要学会啊,光靠别人不行啊
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